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ÀÛ¼ºÀÏ : 05-12-04 22:34
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 ±Û¾´ÀÌ : ¹Ù³ª¹Ù (222.¢½.252.83)
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lim(nÀÌ ¹«ÇÑ´ë·Î)(3^n+2^n)^1/n = 3
 
À§ ¹®Á¦ ´äÀÌ 3Àε¥ ¿Ö ±×·±°¡¿ä?
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´Þº¸´ÙÅ«°Í 05-12-05 00:09
 61.¢½.130.107  
(3^n+2^n)^1/n=[3^n{1+(2/3)^n}]^1/n
                      =3{1+(2/3)^n}^1/n

¿¡¼­ lim¸¦ ¹«ÇÑ´ë·Î °¡Á®°¡¸é 1+(2/3)^n  --> 1·Î ¼ö·Å, 1/n --> 0 À¸·Î ¼ö·Å
                                        °á±¹ 1^0Àº 1ÀÌ µÇÁÒ... µû¶ó¼­ 3 °öÇϱâ 1Àº 3!!
¹Ù³ª¹Ù 05-12-05 00:31
 222.¢½.252.83  
´Þº¸´ÙÅ«°Í´Ô °¨»çÇÕ´Ï´Ù^^
 
 



 
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